Lewis Dot Structure Of So42 [portable] Instant

O=S=O

Connect each oxygen to the sulfur using a single bond (2 electrons each). 4 bonds × 2 electrons = 8 electrons used. Remaining: 32 - 8 = 24 electrons. 4. Distribute Remaining Electrons lewis dot structure of so42

Place the least electronegative atom in the center. In this case, goes in the middle, with four Oxygen atoms surrounding it. 3. Form Single Bonds O=S=O Connect each oxygen to the sulfur using