From equation: 1 mol Mg → 1 mol H₂ So moles H₂ = 0.10 mol Volume H₂ = 0.10 × 24 = 2.4 dm³ (1 mark for mole ratio, 1 mark for volume)
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Before you start, ensure you are downloading the correct papers. Chemistry is offered by different exam boards, and the syllabus content can vary slightly. From equation: 1 mol Mg → 1 mol H₂ So moles H₂ = 0
– 12 dm³ (0.5 mol × 24 dm³/mol = 12 dm³) – 12 dm³ (0
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What is the mass of one mole of carbon dioxide (CO₂)? (Ar: C = 12, O = 16)